The product of the reaction is:

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(A) The reaction involves the nucleophilic ring opening of an epoxide by a Grignard reagent $(RMgX)$.In an unsymmetrical epoxide,the nucleophile $(R^-

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The product is $Ph-CH_2-CH(OH)-CH(R)-CH_3$

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(A) The reaction involves the nucleophilic ring opening of an epoxide by a Grignard reagent $(RMgX)$.In an unsymmetrical epoxide,the nucleophile $(R^-)$ attacks the less sterically hindered carbon atom.The epoxide is $1-phenyl-2,3-epoxybutane$ (or $2-methyl-3-benzyloxirane$).The carbon atom attached to the $CH_3$ group is less sterically hindered compared to the carbon atom attached to the $PhCH_2$ group.Therefore,the $R$ group attacks the carbon atom bearing the $CH_3$ group.After the attack,the $O^-$ is protonated by $H_3O^+$ to form an alcohol.The resulting product is $1-phenyl-3-substituted-butan-2-ol$,which is $Ph-CH_2-CH(OH)-CH(R)-CH_3$.

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