The product obtained is

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The reactant is $3-(hydroxymethyl)cyclohexan-1-ol$. The reagent $Na_2Cr_2O_7 / H_2SO_4$ is a strong oxidizing agent (Jones reagent). It oxidizes p

Vedclass · Accepted Answer

$3-$oxocyclohexanecarboxylic acid

Vedclass · Answer

(A) The reactant is $3-(hydroxymethyl)cyclohexan-1-ol$. The reagent $Na_2Cr_2O_7 / H_2SO_4$ is a strong oxidizing agent (Jones reagent). It oxidizes primary alcohols to carboxylic acids and secondary alcohols to ketones. Therefore,the $1^\circ$ alcohol group $(-CH_2OH)$ is oxidized to a carboxylic acid $(-COOH)$ and the $2^\circ$ alcohol group $(-OH)$ is oxidized to a ketone $(=O)$. The final product is $3-oxocyclohexanecarboxylic acid$.

Similar Questions

Which of the following alcohols is most easily dehydrated with concentrated ${H_2SO_4}$?

The correct order of boiling point for primary $({1^o}),$ secondary $({2^o}),$ and tertiary $({3^o})$ alcohols is

Which of the following compounds is oxidised to prepare methyl ethyl ketone?

Which of the following is a tertiary alcohol?

Which of the following reactions will $NOT$ occur with heated copper at $300\,^oC$?

Vedclass Test Series

Exam Paper Generator

Online Exam Module