The product of HCF(a, b) and LCM(a, b) is equ | vedclass

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Question

(B) For any two positive integers $a$ and $b$,the fundamental theorem of arithmetic states that the product of the two numbers is equal to the product

Vedclass · Accepted Answer

$a 	imes b$

Vedclass · Answer

(B) For any two positive integers $a$ and $b$,the fundamental theorem of arithmetic states that the product of the two numbers is equal to the product of their Highest Common Factor $(HCF)$ and Least Common Multiple $(LCM)$.Mathematically,this is expressed as: $HCF(a, b) 	imes LCM(a, b) = a 	imes b$.

The product of $HCF(a, b)$ and $LCM(a, b)$ is equal to:

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