The product of the reaction will be :

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Question

(C) The given reaction is a Perkin condensation reaction. In this reaction,an aromatic aldehyde reacts with an acid anhydride in the presence of the s

Vedclass · Accepted Answer

$O_2N-C_6H_4-CH=C(C_6H_5)-COOH$

Vedclass · Answer

(C) The given reaction is a Perkin condensation reaction. In this reaction,an aromatic aldehyde reacts with an acid anhydride in the presence of the sodium salt of the corresponding acid. The general reaction is: $Ar-CHO + (R-CH_2-CO)_2O \xrightarrow{R-CH_2-COONa/\Delta} Ar-CH=C(R)-COOH$. Here,$Ar = p-NO_2-C_6H_4-$ and $R = C_6H_5-$. Substituting these into the general formula,we get the product as $p-NO_2-C_6H_4-CH=C(C_6H_5)-COOH$.

Similar Questions

Identify the correct decreasing order of acidic strength for the following compounds:
$I$: $p$-Nitrobenzoic acid
$II$: Benzoic acid
$III$: $p$-Methoxybenzoic acid

What are $X$ and $Y$ respectively in the following reaction sequence?
Styrene $\xrightarrow[(ii) H_3O^+]{(i) KMnO_4 / KOH} X$ $\xrightarrow{Br_2 / FeBr_3} Y$

Which of the following is the correct order of acidity?

Which one of the following compounds does not give benzoic acid when treated with alkaline $KMnO_4$?

The product $(A)$ is:

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