The products A and B formed in the following | vedclass

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(C) $1$. The reaction of benzene with $conc. HNO_3$ and $conc. H_2SO_4$ at $323-333 \ K$ gives nitrobenzene.$2$. Reduction of nitrobenzene with $Sn/HC

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Aniline,$p$-hydroxyazobenzene

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(C) $1$. The reaction of benzene with $conc. HNO_3$ and $conc. H_2SO_4$ at $323-333 \ K$ gives nitrobenzene.$2$. Reduction of nitrobenzene with $Sn/HCl$ gives aniline $(A)$.$3$. Aniline reacts with $NaNO_2/HCl$ at $273-278 \ K$ $(0-5^{\circ}C)$ to form benzenediazonium chloride.$4$. Coupling of benzenediazonium chloride with phenol in a basic medium yields $p$-hydroxyazobenzene $(B)$.

The products $A$ and $B$ formed in the following reaction scheme are respectively:

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