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(D) The reaction of $HC \equiv C-CH_2-CH_2-COCH_3$ with $HgSO_4$ and dilute $H_2SO_4$ is a hydration reaction of an alkyne. The terminal alkyne underg

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$CH_3COCH_2CH_2COCH_3$,$3$-methylcyclopent-$2$-en-$1$-one

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(D) The reaction of $HC \equiv C-CH_2-CH_2-COCH_3$ with $HgSO_4$ and dilute $H_2SO_4$ is a hydration reaction of an alkyne. The terminal alkyne undergoes hydration to form a ketone. The product $A$ is $CH_3COCH_2CH_2COCH_3$ (hexane-$2,5$-dione).Next,the reaction of $CH_3COCH_2CH_2COCH_3$ with $EtONa$ and $EtOH$ is an intramolecular aldol condensation. The base $EtO^-$ abstracts an $\alpha$-hydrogen from one of the methyl groups,forming an enolate,which then attacks the other carbonyl group to form a five-membered ring. Subsequent dehydration yields $3$-methylcyclopent-$2$-en-$1$-one as product $B$.

The products $A$ and $B$ of the below reaction sequence are

Similar Questions

Identify $A$ in the given chemical reaction:

The compound $(P)$ undergoes the following reaction sequence: $(P)$ $\xrightarrow{\Delta} X$ $\xrightarrow{Zn-Hg/HCl} Y$. Identify $Y$.

Compounds $A$ and $B$,both were treated with $NaOH$,producing a single compound $C$. Identify compound $C$.

The reaction of $A$ to give $B$ and $C$ as shown in the reaction scheme is an example of:
$CH_2=CH_2$ $\xrightarrow[2. Zn/H_2O]{1. O_3} A$ $\xrightarrow{Conc. NaOH} B + C$
(Where $B$ is an alcohol and $C$ is a sodium salt of a carboxylic acid)

Compound '$X$' (molecular formula $C_3H_8O$) reacts with acidic potassium dichromate to give product '$Y$' (molecular formula $C_3H_6O$). '$Y$' gives a silver mirror test. When '$Y$' is reacted with aqueous $NH_2CONHNH_2$ and sodium acetate,it gives product '$Z$'. What is the structure of '$Z$'?

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