The radioactive isotope _{27}^{60}Co,which is | vedclass

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Question

(A) An $(n, p)$ reaction involves the capture of a neutron and the emission of a proton.For the production of $_{27}^{60}Co$ from a target nucleus $X$

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$_{28}^{60}Ni$

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(A) An $(n, p)$ reaction involves the capture of a neutron and the emission of a proton.For the production of $_{27}^{60}Co$ from a target nucleus $X$ via $(n, p)$ reaction,the equation is: $_{Z}^{A}X + _{0}^{1}n \rightarrow _{27}^{60}Co + _{1}^{1}p$.By balancing the mass number: $A + 1 = 60 + 1$,so $A = 60$.By balancing the atomic number: $Z + 0 = 27 + 1$,so $Z = 28$.The target nucleus is $_{28}^{60}Ni$.

The radioactive isotope $_{27}^{60}Co$,which is used in the treatment of cancer,can be produced by an $(n, p)$ reaction. For this reaction,the target nucleus is:

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