The radius of a circle is $3.5\,cm$. The area of the minor sector formed by two perpendicular radii of that circle is $\ldots \ldots \ldots \,cm^2$.

  • A
    $19.25$
  • B
    $9.625$
  • C
    $38.5$
  • D
    $77$

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Similar Questions

In $\odot(O, r)$,chord $\overline{AB}$ subtends a right angle at the centre. The area of the minor segment $\overline{AB} \cup \widehat{ACB}$ is $114 \, cm^2$ and the area of $\Delta OAB$ is $200 \, cm^2$. Then,the area of the minor sector $OACB$ is ......... $cm^2$.

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Find the difference of the areas of two segments of a circle formed by a chord of length $5 \, cm$ subtending an angle of $90^{\circ}$ at the centre.

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The diameter of a circle with area $154\,cm^{2}$ is $\ldots \ldots \ldots . cm$.

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