The radius of a thin wire is 0.16 ; mm. The a | vedclass

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(B) The area of the cross-section of a wire is given by the formula $A = \pi r^2$.Given the radius $r = 0.16 \; mm$.Substituting the value,$A = \pi

Vedclass · Accepted Answer

$0.080$

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(B) The area of the cross-section of a wire is given by the formula $A = \pi r^2$.Given the radius $r = 0.16 \; mm$.Substituting the value,$A = \pi 	imes (0.16 \; mm)^2 = 3.14159 	imes 0.0256 \; mm^2 \approx 0.0804247 \; mm^2$.According to the rules of significant figures,the result of a multiplication should have the same number of significant figures as the measurement with the fewest significant figures.The radius $0.16 \; mm$ has $2$ significant figures.Therefore,the final result must be rounded to $2$ significant figures.Rounding $0.0804247$ to $2$ significant figures gives $0.080 \; mm^2$.

Column-$I$	Column-$II$
$(a)$ $0.007\ m^2$	$(p)$ $2$
$(b)$ $2.64 \times 10^{24}\ kg$	$(q)$ $1$
$(c)$ $0.0021\ g\ cm^{-3}$	$(r)$ $4$
$(d)$ $0.0006032\ J$	$(s)$ $3$

The radius of a thin wire is $0.16 \; mm$. The area of cross-section taking significant figures into consideration in square millimeters is?

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