The radius of the base of a cone is 10 , cm a | vedclass

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(A) For a given cone:Radius $(r) = 10 \, cm$ and slant height $(l) = 26 \, cm$.Using the relation $l^2 = r^2 + h^2$,we find the height $(h)$:$h^2 = l^

Vedclass · Accepted Answer

$2512$

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(A) For a given cone:Radius $(r) = 10 \, cm$ and slant height $(l) = 26 \, cm$.Using the relation $l^2 = r^2 + h^2$,we find the height $(h)$:$h^2 = l^2 - r^2$$h^2 = (26)^2 - (10)^2$$h^2 = 676 - 100 = 576$$h = \sqrt{576} = 24 \, cm$.The volume of a cone is given by the formula $V = \frac{1}{3} \pi r^2 h$.$V = \frac{1}{3} 	imes 3.14 	imes (10)^2 	imes 24$$V = 3.14 	imes 100 	imes 8$$V = 314 	imes 8 = 2512 \, cm^3$.

The radius of the base of a cone is $10 \, cm$ and its slant height is $26 \, cm$. Find the volume of the cone. $(\pi = 3.14)$ (in $cm^3$)

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