Medium
The rate constant for a second order reaction is $8 \times 10^{-5} \ M^{-1} \ min^{-1}$. How long will it take a $1 \ M$ solution to be reduced to $0.5 \ M$?
- A$8 \times 10^{-5} \ min$
- B$8.665 \times 10^{3} \ min$
- C$4 \times 10^{-5} \ min$
- D$1.25 \times 10^{4} \ min$
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Medium
View SolutionConsider the following two reactions:
$A \to \text{Product}; -\frac{d[A]}{dt} = k_1[A]^0$
$B \to \text{Product}; -\frac{d[B]}{dt} = k_2[B]$
The units of $k_1$ and $k_2$ are expressed in terms of molarity $(M)$ and time $(sec^{-1})$ as:
$A \to \text{Product}; -\frac{d[A]}{dt} = k_1[A]^0$
$B \to \text{Product}; -\frac{d[B]}{dt} = k_2[B]$
The units of $k_1$ and $k_2$ are expressed in terms of molarity $(M)$ and time $(sec^{-1})$ as:
Medium
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