The rate constant of the reaction A rightarro | vedclass

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(C) The reaction is of zero order because the units of the rate constant are $mol \, L^{-1} \, s^{-1}.$For a zero order reaction,the change in concent

Vedclass · Accepted Answer

$0.72$

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(C) The reaction is of zero order because the units of the rate constant are $mol \, L^{-1} \, s^{-1}.$For a zero order reaction,the change in concentration $x$ is given by $x = K \cdot t.$Given $K = 0.6 	imes 10^{-3} \, mol \, L^{-1} \, s^{-1}$ and $t = 20 \, 	ext{minutes} = 20 	imes 60 \, s = 1200 \, s.$Substituting the values: $x = (0.6 	imes 10^{-3}) 	imes 1200 = 0.72 \, M.$Thus,the concentration of $B$ formed after $20$ minutes is $0.72 \, M.$

$[R] \ (M)$	$1.0$	$0.76$	$0.40$	$0.10$
$t \ (min)$	$0.0$	$0.05$	$0.12$	$0.18$

The rate constant of the reaction $A \rightarrow B$ is $0.6 \times 10^{-3} \, mol \, L^{-1} \, s^{-1}.$ If the concentration of $A$ is $5 \, M,$ then the concentration of $B$ after $20$ minutes is ......... $M.$

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For the reaction $R \rightarrow P$,the concentration of $R$ is measured as a function of time and the following data is obtained:

$[R] \ (M)$ $1.0$ $0.76$ $0.40$ $0.10$

$t \ (min)$ $0.0$ $0.05$ $0.12$ $0.18$

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For a zero order reaction,the plot of concentration of reactant $vs$ time is (Hint: Consider the intercept on the concentration axis)

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