The rate of nitration will be

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(C) The rate-determining step in electrophilic aromatic substitution (nitration) is the formation of the $\sigma$-complex (arenium ion) by the attack

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$a = b = c$

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(C) The rate-determining step in electrophilic aromatic substitution (nitration) is the formation of the $\sigma$-complex (arenium ion) by the attack of the nitronium ion $(NO_2^+)$ on the aromatic ring. Since the $C-H$ or $C-D$ bond fission occurs after the rate-determining step,there is no primary kinetic isotope effect observed. The methyl group $(Me)$ exerts the same steric effect in all three substrates,and the attacking electrophile is identical. Therefore,the rates of nitration for all three substrates $(a, b, c)$ are the same.

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