The ratio of alcohol and water in 40 litres o | vedclass

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(B) Initial mixture $= 40$ litres.Ratio of alcohol to water $= 5:3$.When $8$ litres of the mixture is removed,the remaining mixture $= 40 - 8 = 32$ li

Vedclass · Accepted Answer

$1:1$

Vedclass · Answer

(B) Initial mixture $= 40$ litres.Ratio of alcohol to water $= 5:3$.When $8$ litres of the mixture is removed,the remaining mixture $= 40 - 8 = 32$ litres.In the remaining $32$ litres,the amount of alcohol $= \frac{5}{8} 	imes 32 = 20$ litres.The amount of water $= \frac{3}{8} 	imes 32 = 12$ litres.Now,$8$ litres of water is added to the mixture.New amount of alcohol $= 20$ litres.New amount of water $= 12 + 8 = 20$ litres.Therefore,the required ratio of alcohol to water $= 20:20 = 1:1$.

The ratio of alcohol and water in $40$ $litres$ of mixture is $5:3$. Then $8$ $litres$ of the mixture is removed and replaced with water. Now,the ratio of the alcohol and water in the resultant mixture is

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