The ratio of the average electric energy dens | vedclass

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Question

(D) In an electromagnetic wave,the average electric energy density $\langle u_E \rangle$ and the average magnetic energy density $\langle u_B \rangle$

Vedclass · Accepted Answer

$\frac{1}{2}$

Vedclass · Answer

(D) In an electromagnetic wave,the average electric energy density $\langle u_E angle$ and the average magnetic energy density $\langle u_B angle$ are equal.$\langle u_E angle = \langle u_B angle$The total average energy density $\langle u_{	ext{total}} angle$ is the sum of the average electric and magnetic energy densities:$\langle u_{	ext{total}} angle = \langle u_E angle + \langle u_B angle = 2 \langle u_E angle$Therefore,the ratio of the average electric energy density to the total average energy density is:$\frac{\langle u_E angle}{\langle u_{	ext{total}} angle} = \frac{\langle u_E angle}{2 \langle u_E angle} = \frac{1}{2}$

The ratio of the average electric energy density to the total average energy density of an electromagnetic wave is:

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