The ratio of specific heats of a gas is gamma | vedclass

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(C) For an ideal gas, the change in internal energy $\Delta U$ is given by $\Delta U = n C_V \Delta T$.Given $n = 1$ mole, so $\Delta U = C_V \Delta T

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$\frac{p V}{\gamma-1}$

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(C) For an ideal gas, the change in internal energy $\Delta U$ is given by $\Delta U = n C_V \Delta T$.Given $n = 1$ mole, so $\Delta U = C_V \Delta T$.We know that $C_V = \frac{R}{\gamma-1}$.Thus, $\Delta U = \frac{R \Delta T}{\gamma-1}$.From the ideal gas equation at constant pressure $p$, $p V = R T$, so $p \Delta V = R \Delta T$.Here, the volume changes from $V$ to $2V$, so $\Delta V = 2V - V = V$.Therefore, $R \Delta T = p V$.Substituting this into the expression for $\Delta U$:$\Delta U = \frac{p V}{\gamma-1}$.

The ratio of specific heats of a gas is $\gamma$. The change in internal energy of one mole of the gas, when the volume changes from $V$ to $2V$ at constant pressure $p$, is:

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