The ratio of the ages of Ram and Rahim $10 \text{ yr}$ ago was $1:3$. The ratio of their ages $5 \text{ yr}$ hence will be $2:3$. Then,the ratio of their present ages is:

If $\frac{5a+3b}{2a-3b} = \frac{23}{5}$,then the value of $a:b$ is:

The sum of the present ages of a father and his son is $90$ years. $10$ years ago,the ratio of their ages was $5:2$. The present age of the father is (in years):

$A$ mixture contains alcohol and water in the ratio $4:3$. If $5 \text{ liters}$ of water is added to the mixture,the ratio becomes $4:5$. Find the quantity of alcohol in the given mixture (in $\text{L}$).

If the income of $A$,$B$,and $C$ is in the ratio of $2: 5: 11$ and the income of $B$ is ₹ $291$ more than that of $A$,then the income of $C$ is (in ₹).

If $A: B = 3: 4$ and $B: C = 8: 9$,then find the value of $A: B: C$.