The ratio of the distances of two planets from the sun is $1.38$. The ratio of their period of revolution around the sun is

$A$ satellite is launched into a circular orbit of radius $R$ around Earth,while a second satellite is launched into an orbit of radius $1.02 R$. The percentage difference in the time periods of the two satellites is:

Two planets revolve around the sun with frequencies ${N_1}$ and ${N_2}$ revolutions per year. If their average orbital radii are ${R_1}$ and ${R_2}$ respectively,then ${R_1}/{R_2}$ is equal to:

The distance of a planet from the sun is $5$ times the distance between the earth and the sun. The time period of the planet is

If the radius of the Earth's orbit is made $\frac{1}{4}$ of its original value,the duration of a year will become:

The figure shows an elliptical orbit of a planet of mass $m$ about the sun $S.$ The shaded area $SCD$ is twice the shaded area $SAB.$ If $t_1$ is the time taken for the planet to move from $C$ to $D$ and $t_2$ is the time taken to move from $A$ to $B,$ then: