The ratio of the magnitude of the magnetic fi | vedclass

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Question

(B) For a plane electromagnetic wave in free space,the relationship between the magnitude of the electric field $(E_0)$ and the magnetic field $(B_0)$

Vedclass · Accepted Answer

$\frac{1}{c}$

Vedclass · Answer

(B) For a plane electromagnetic wave in free space,the relationship between the magnitude of the electric field $(E_0)$ and the magnetic field $(B_0)$ is given by $E_0 = c B_0$,where $c$ is the speed of light in free space.Therefore,the ratio of the magnitude of the magnetic field to the electric field intensity is $\frac{B_0}{E_0} = \frac{1}{c}$.Since the speed of light in free space is defined as $c = \frac{1}{\sqrt{\mu_0 \varepsilon_0}}$,we can also express this ratio as $\frac{B_0}{E_0} = \sqrt{\mu_0 \varepsilon_0}$.However,in terms of the given options,the correct ratio is $\frac{1}{c}$.

The ratio of the magnitude of the magnetic field $(B_0)$ and electric field intensity $(E_0)$ of a plane electromagnetic wave in free space with permeability $\mu_0$ and permittivity $\varepsilon_0$ is (Given that $c$ is the velocity of light in free space):

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