The ratio of the radii of the second and thir | vedclass

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(D) The radius of the $n^{th}$ orbit is given by $r_{n} \propto \frac{n^{2}}{Z}$.For an $H$-atom,the atomic number $Z = 1$.Therefore,the radius is pro

Vedclass · Accepted Answer

$4: 9$

Vedclass · Answer

(D) The radius of the $n^{th}$ orbit is given by $r_{n} \propto \frac{n^{2}}{Z}$.For an $H$-atom,the atomic number $Z = 1$.Therefore,the radius is proportional to the square of the principal quantum number: $r_{n} \propto n^{2}$.For the second orbit $(n_{2} = 2)$ and the third orbit $(n_{3} = 3)$:$\frac{r_{2}}{r_{3}} = \left(\frac{n_{2}}{n_{3}}\right)^{2} = \left(\frac{2}{3}\right)^{2} = \frac{4}{9}$.Thus,the ratio is $4: 9$.

The ratio of the radii of the second and third orbits of an $H$-atom is . . . . . . .

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