The ratios of the sides in a triangle are 5:1 | vedclass

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(C) Let the sides of the triangle be $5x, 12x, 13x$. Since $5^2 + 12^2 = 25 + 144 = 169 = 13^2$,the triangle is a right-angled triangle. The area of a

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$15, 36, 39$

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(C) Let the sides of the triangle be $5x, 12x, 13x$. Since $5^2 + 12^2 = 25 + 144 = 169 = 13^2$,the triangle is a right-angled triangle. The area of a right-angled triangle is given by $\Delta = \frac{1}{2} 	imes 	ext{base} 	imes 	ext{height} = \frac{1}{2} 	imes (5x) 	imes (12x)$. Given $\Delta = 270 	ext{ cm}^2$,we have $30x^2 = 270$. $x^2 = 9$,which implies $x = 3$. Therefore,the sides are $5(3), 12(3), 13(3)$,which are $15 	ext{ cm}, 36 	ext{ cm}, 39 	ext{ cm}$.

The ratios of the sides in a triangle are $5:12:13$ and its area is $270 \text{ cm}^2$. The sides of the triangle in $\text{cm}$ are

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