The reactance of a 25,mu F capacitor at the a | vedclass

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(A) The capacitive reactance $X_C$ is given by the formula $X_C = \frac{1}{2\pi 
u C}$.Given values are frequency $
u = 4000\, Hz$ and capacitance $

Vedclass · Accepted Answer

$\frac{5}{\pi }\,\Omega$

Vedclass · Answer

(A) The capacitive reactance $X_C$ is given by the formula $X_C = \frac{1}{2\pi 
u C}$.Given values are frequency $
u = 4000\, Hz$ and capacitance $C = 25\,\mu F = 25 	imes 10^{-6}\, F$.Substituting these values into the formula:$X_C = \frac{1}{2 	imes \pi 	imes 4000 	imes 25 	imes 10^{-6}}$$X_C = \frac{1}{2 	imes \pi 	imes 10^5 	imes 10^{-6}}$$X_C = \frac{1}{2 	imes \pi 	imes 10^{-1}}$$X_C = \frac{1}{0.2 	imes \pi} = \frac{10}{2\pi} = \frac{5}{\pi}\,\Omega$.

The reactance of a $25\,\mu F$ capacitor at the ac frequency of $4000\, Hz$ is

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