The reaction 2SO_2 + O_2 rightleftharpoons 2S | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The given reaction is $2SO_2(g) + O_2(g) \rightleftharpoons 2SO_3(g)$; $\Delta H = -ve$. Since $\Delta H$ is negative,the reaction is exothermic.

Vedclass · Accepted Answer

Low temperature,high pressure

Vedclass · Answer

(B) The given reaction is $2SO_2(g) + O_2(g) \rightleftharpoons 2SO_3(g)$; $\Delta H = -ve$. Since $\Delta H$ is negative,the reaction is exothermic. According to Le Chatelier's principle,for an exothermic reaction,a low temperature favours the forward reaction. Regarding pressure,the number of moles of gaseous reactants is $2 + 1 = 3$,and the number of moles of gaseous products is $2$. Since the number of moles decreases in the forward direction,high pressure favours the forward reaction. Therefore,the reaction is favoured by low temperature and high pressure.

The reaction $2SO_2 + O_2 \rightleftharpoons 2SO_3$; $\Delta H = -ve$ is favoured by

Similar Questions

The exothermic formation of $ClF_3$ is represented by the equation
$Cl_{2(g)} + 3F_{2(g)} \rightleftharpoons 2ClF_{3(g)}$; $\Delta H_r = -329 \ kJ$
Which of the following will increase the quantity of $ClF_3$ in an equilibrium mixture of $Cl_2, F_2$ and $ClF_3$?

The yield of the products in the reaction,$A_{2(g)} + 2B_{(g)} \rightleftharpoons C_{(g)} + Q \ kJ$ would be higher at

What happens when an inert gas is added at constant pressure to a reversible decomposition reaction that is in equilibrium?

At equilibrium,what happens to the boiling point of $H_2O$ when pressure is increased?

In which of the following reactions will an increase in pressure shift the equilibrium in the backward direction?

Vedclass Test Series

Exam Paper Generator

Online Exam Module