The reaction $2A_{(g)} + B_{(g)} \rightleftharpoons 3C_{(g)} + D_{(g)}$ is begun with the concentrations of $A$ and $B$ both at an initial value of $1.00 \ M$. When equilibrium is reached,the concentration of $D$ is measured and found to be $0.25 \ M$. The value for the equilibrium constant for this reaction is given by the expression

  • A
    $[(0.75)^3 (0.25)] \div [(0.75)^2 (0.25)]$
  • B
    $[(0.75)^3 (0.25)] \div [(1.00)^2 (1.00)]$
  • C
    $[(0.75)^3 (0.25)] \div [(0.50)^2 (0.75)]$
  • D
    $[(0.75)^3 (0.25)] \div [(0.50)^2 (0.25)]$

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