The reaction H_2S + H_2O_2 to 2H_2O + S shows | vedclass

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(A) In the reaction $H_2S + H_2O_2 	o 2H_2O + S$,the oxidation state of sulfur in $H_2S$ changes from $-2$ to $0$ (oxidation).The oxidation state of

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Oxidizing action of $H_2O_2$

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(A) In the reaction $H_2S + H_2O_2 	o 2H_2O + S$,the oxidation state of sulfur in $H_2S$ changes from $-2$ to $0$ (oxidation).The oxidation state of oxygen in $H_2O_2$ changes from $-1$ to $-2$ (reduction).Since $H_2O_2$ undergoes reduction,it acts as an oxidizing agent.Therefore,the reaction shows the oxidizing action of $H_2O_2$.

The reaction $H_2S + H_2O_2 \to 2H_2O + S$ shows:

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