The reaction 2 C_6H_6 + CH_2Cl_2 xrightarrow{ | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The reaction is a Friedel-Crafts alkylation. Benzene reacts with dichloromethane $(CH_2Cl_2)$ in the presence of a Lewis acid catalyst like $AlCl_

Vedclass · Accepted Answer

$Ph-CH_2-Ph$

Vedclass · Answer

(B) The reaction is a Friedel-Crafts alkylation. Benzene reacts with dichloromethane $(CH_2Cl_2)$ in the presence of a Lewis acid catalyst like $AlCl_3$. The electrophile $CH_2Cl^{+}$ attacks the benzene ring to form benzyl chloride $(Ph-CH_2Cl)$. This intermediate then reacts with another molecule of benzene to form diphenylmethane $(Ph-CH_2-Ph)$. The overall reaction is: $2 C_6H_6 + CH_2Cl_2 \xrightarrow{AlCl_3} Ph-CH_2-Ph + 2 HCl$.

The reaction $2 C_6H_6 + CH_2Cl_2 \xrightarrow{AlCl_3, \Delta} ?$ gives the major product:

Similar Questions

Which one of the following methods is suitable to generate aromatic compound$(s)$ from linear aliphatic saturated hydrocarbons with at least six carbon atoms?

$A$ substance containing an equal number of primary,secondary and tertiary carbon atoms is:

Which of the following statements is incorrect regarding the nitration of aromatic compounds?

Identify the number of aromatic compounds from the following structures:
$(i)$ $1,2,4$-triazole
(ii) $2$-pyrone
(iii) Benzimidazole
(iv) Pyrazole
$(v)$ Cyclooctatetraene dianion
(vi) Pyrrolidinium cation
(vii) Cyclopentadienyl cation

The hybridization involved in the six carbon atoms of benzene is

Vedclass Test Series

Exam Paper Generator

Online Exam Module