The reaction of HBr with the following compou | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The reaction of $HBr$ with $4-hydroxystilbene$ $(Ph-CH=CH-C_6H_4-OH)$ follows Markovnikov's rule. $1$. The double bond attacks the $H^+$ from $HBr

Vedclass · Accepted Answer

$1-$($4$-hydroxyphenyl)$-1-$bromo$-2-$phenylethane

Vedclass · Answer

(A) The reaction of $HBr$ with $4-hydroxystilbene$ $(Ph-CH=CH-C_6H_4-OH)$ follows Markovnikov's rule. $1$. The double bond attacks the $H^+$ from $HBr$ to form the most stable carbocation. $2$. The carbocation formed at the benzylic position adjacent to the $4-hydroxyphenyl$ ring is more stable due to resonance stabilization from both the phenyl ring and the lone pair on the oxygen atom of the $-OH$ group. $3$. The bromide ion $(Br^-)$ then attacks this stable carbocation to form $1-(4-hydroxyphenyl)-1-bromo-2-phenylethane$.

The reaction of $HBr$ with the following compound would produce:

Similar Questions

Taking into account the stability of various cycloalkanes and carbocations,as well as the rules governing mechanisms of carbocation rearrangements,what is the most likely product of this reaction?

In the following sequence of reactions,the alkene affords the compound $B$.
$CH_3-CH=CH-CH_3$ $\xrightarrow{O_3} A$ $\xrightarrow[Zn]{H_2O} B$
The compound $B$ is:

$A$ hydrocarbon has a molecular mass of $84 \ g/mol$. What is the number of its structural chain isomers?

Bromination of cyclohexene under the conditions given below yields:
Cyclohexene $\xrightarrow{Br_2/hv}$ ?

Surprisingly,the reaction shown below goes through a classical carbocation. What is the major product of this reaction?

Vedclass Test Series

Exam Paper Generator

Online Exam Module