The reaction of 4-methyloct-1-ene (P, 2.52 g | vedclass

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(B) $1$. Moles of $P$ ($4$-methyloct$-1-$ene) = $\frac{2.52 \ g}{126 \ g \ mol^{-1}} = 0.02 \ mol$.$2$. The reaction with $HBr$ in the presence of per

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$1791$

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(B) $1$. Moles of $P$ ($4$-methyloct$-1-$ene) = $\frac{2.52 \ g}{126 \ g \ mol^{-1}} = 0.02 \ mol$.$2$. The reaction with $HBr$ in the presence of peroxide follows anti-Markovnikov addition. The combined yield is $50 \%$,so the total moles of bromides formed = $0.02 	imes 0.50 = 0.01 \ mol$.$3$. The bromides are formed in a $9:1$ ratio. The primary alkyl bromide is the major product ($9$ parts out of $10$).$4$. Moles of primary alkyl bromide = $\frac{9}{10} 	imes 0.01 \ mol = 0.009 \ mol$.$5$. The primary alkyl bromide reacts with diethylamine to form a quaternary ammonium salt,which upon treatment with aqueous $K_2CO_3$ yields the non-ionic amine product $S$.$6$. The molar mass of $S$ ($N,N$-diethyl$-4$-methyloctan$-1-$amine) is $199 \ g \ mol^{-1}$.$7$. Mass of $S$ = $	ext{moles} 	imes 	ext{molar mass} = 0.009 \ mol 	imes 199 \ g \ mol^{-1} = 1.791 \ g = 1791 \ mg$.

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