The reaction of calcium carbide with water produces.......

In the reaction sequence:
$CH_3-C\equiv CH$ $\xrightarrow{CH_3MgBr}$ $CH_4 + (A)$ $\xrightarrow[ (ii) H_2O/H^{\oplus} ]{(i) CO_2}$ $(B)$
$(B)$ will be:

$A \xrightarrow{Ag_2O} \text{ppt}$
$A$ $\xrightarrow{Hg^{2+} / H^{+}} B$ $\xrightarrow{NaBH_4} C$ $\xrightarrow{conc. HCl / ZnCl_2} \text{Turbidity within 5 minutes}$.
Consider the following reactions,'$A$' is:

Consider the following reaction sequence:
$CH_3CH_2CH_2CH(Br)CH_2Br + 2NaNH_2 \rightarrow X$
$X \xrightarrow[(ii) (CH_3)_2CHBr]{(i) NaNH_2} Y$
The product $Y$ formed is:

The compound $X \ (C_5H_8)$ reacts with ammoniacal $AgNO_3$ to give a white precipitate and reacts with excess of $KMnO_4$ to give the acid,$(CH_3)_2CHCOOH$. Therefore,$X$ is:

$CH \equiv CH$ $\xrightarrow{O_3/NaOH} X$ $\xrightarrow{Zn/CH_3COOH} Y$. '$Y$' is: