The reaction of nitroprusside anion with sulphide ion gives purple colouration due to the formation of

  • A
    the tetranionic complex of iron $(II)$ coordinating to one $NOS^{4-}$ ion
  • B
    the dianionic complex of iron $(II)$ coordinating to one $NCS^{-}$ ion
  • C
    the trianionic complex of iron $(III)$ coordinating to one $NOS^{-}$ ion
  • D
    the tetranionic complex of iron $(III)$ coordinating to one $NCS^{-}$ ion

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$5.33 \text{ g}$ of $CrCl_3 \cdot 6H_2O$, which is a $1:3$ electrolyte, is dissolved in water and passed through a cation exchanger. The chloride ions in the eluted solution, on treatment with $AgNO_3$, result in $8.61 \text{ g}$ of $AgCl$. The ratio of moles of complex reacted and moles of $AgCl$ formed is . . . . . . $\times 10^{-2}$. (Nearest integer) [Molar mass in $\text{g mol}^{-1}$: $Cr = 52, Ag = 108, Cl = 35.5, H = 1, O = 16$]

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