The reaction of propene with H_3O^{+} proceed | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The reaction of propene $(CH_3-CH=CH_2)$ with $H_3O^{+}$ (acid-catalyzed hydration) follows Markovnikov's rule.In the first step,a proton $(H^{+})

Vedclass · Accepted Answer

$CH_3-CH(O^{+}H_2)-CH_3$

Vedclass · Answer

(C) The reaction of propene $(CH_3-CH=CH_2)$ with $H_3O^{+}$ (acid-catalyzed hydration) follows Markovnikov's rule.In the first step,a proton $(H^{+})$ adds to the terminal carbon to form the more stable secondary carbocation $(CH_3-C^{+}H-CH_3)$.In the second step,water $(H_2O)$ acts as a nucleophile and attacks the carbocation to form the oxonium ion intermediate $CH_3-CH(O^{+}H_2)-CH_3$.

The reaction of propene with $H_3O^{+}$ proceeds through which of the following intermediates?

Similar Questions

When an alcoholic solution of ethylene dibromide $(Br-CH_2-CH_2-Br)$ is heated with granulated zinc,the compound formed is:

Write the main product of the given reactions:
$(1)$ $CH_3CH = CHCH_3 + HBr \to$
$(2)$ $CH_3-C(CH_3)=CH_2 + HBr \to$

Ethene when treated with $Br_2$ in the presence of $CCl_4$,which compound is formed?

What product is formed when the alkene $R-CH=CH_2$ reacts with $B_2H_6$ in the presence of $H_2O_2$?

Out of the following,the alkene that exhibits optical isomerism is

Vedclass Test Series

Exam Paper Generator

Online Exam Module