The reaction of toluene with $Cl_2$ in the presence of $FeCl_3$ gives $X$ and the reaction in the presence of light gives $Y.$ Thus,$X$ and $Y$ are

  • A
    $X =$ Benzal chloride,$Y = o-$chlorotoluene
  • B
    $X = m-$chlorotoluene,$Y = p-$chlorotoluene
  • C
    $X = o-$ and $p-$chlorotoluene,$Y =$ Trichloromethyl benzene
  • D
    $X =$ Benzyl chloride,$Y = m-$chlorotoluene

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Consider the above sequence of reactions. $151 \ g$ of $2-$bromopentane is made to react. The yield of the major product $P$ is $80 \%$ whereas the yield of $Q$ is $100 \%$. The mass of product $Q$ obtained is $........ \ g$. (Given molar mass in $g \ mol^{-1}$: $H: 1, C: 12, Br: 80$)

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