The reaction that gives the following molecul | vedclass

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(B) The reaction is known as the Williamson synthesis,which is an important laboratory method for the preparation of symmetrical and unsymmetrical eth

Vedclass · Accepted Answer

$(CH_3)_3C-ONa + CH_3Br$

Vedclass · Answer

(B) The reaction is known as the Williamson synthesis,which is an important laboratory method for the preparation of symmetrical and unsymmetrical ethers.For the synthesis of tert-butyl methyl ether,$(CH_3)_3C-OCH_3$,we must use a primary alkyl halide and a tertiary alkoxide to avoid the elimination reaction that would occur if a tertiary alkyl halide were used.Therefore,the reaction between sodium tert-butoxide,$(CH_3)_3C-ONa$,and methyl bromide,$CH_3Br$,is the correct path to obtain the desired ether as the major product.Option $B$ represents this correct reaction: $(CH_3)_3C-ONa + CH_3Br \rightarrow (CH_3)_3C-OCH_3 + NaBr$.

The reaction that gives the following molecule as the major product is:

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$(CH_3)_3C-OCH_3 + HI \rightarrow A + B$

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