The reading of the ammeter in the circuit is ............ $A$.

  • A
    $2$
  • B
    $3$
  • C
    $0$
  • D
    $1$

Explore More

Similar Questions

In an electrical circuit,$R, L, C$ and an $AC$ voltage source are all connected in series. When $L$ is removed from the circuit,the phase difference between the voltage and the current in the circuit is $\pi / 3$. If instead,$C$ is removed from the circuit,the phase difference is again $\pi / 3$. The power factor of the circuit is

Difficult
View Solution

$A$ series $AC$ circuit containing an inductor $(20\,mH),$ a capacitor $(120\,\mu F)$ and a resistor $(60\,\Omega)$ is driven by an $AC$ source of $24\,V$ and $50\,Hz.$ The energy dissipated in the circuit in $60\,s$ is

In an $LCR$ series circuit,$R = 18 \ \Omega$ and the impedance $Z = 33 \ \Omega$. An $r.m.s.$ voltage of $V_{rms} = 220 \ V$ is applied across the circuit. The true power consumed in the $a.c.$ circuit is: (in $W$)

In the circuit diagram shown,$X_C = 100 \, \Omega$,$X_L = 200 \, \Omega$,and $R = 100 \, \Omega$. The source voltage is $V = 200 \sin(\omega t) \, \text{V}$. The effective $(RMS)$ current through the source is:

Difficult
View Solution

An $LCR$ series circuit with a resistance of $100 \, \Omega$ is connected to an $ac$ source of $200 \, V \, (r.m.s.)$ and angular frequency $300 \, rad/s$. When only the capacitor is removed, the current lags behind the voltage by $60^o$. When only the inductor is removed, the current leads the voltage by $60^o$. The average power dissipated is.....$W$

Difficult
View Solution

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo