The reading of the ammeter in the following c | vedclass

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(A) In the given circuit,the first Zener diode (top) is connected in forward bias,so it acts as a simple conducting wire with negligible voltage drop.

Vedclass · Accepted Answer

$0.5$

Vedclass · Answer

(A) In the given circuit,the first Zener diode (top) is connected in forward bias,so it acts as a simple conducting wire with negligible voltage drop.The second Zener diode (bottom) is connected in reverse bias. Since the source voltage is $20 \, V$ and the Zener breakdown voltage of the second diode is $V_{z2} = 15 \, V$,the diode will operate in the breakdown region.The voltage drop across the $10 \, k\Omega$ resistor is $V_R = V_{source} - V_{z2} = 20 \, V - 15 \, V = 5 \, V$.The current $I$ through the circuit is given by Ohm's law: $I = \frac{V_R}{R} = \frac{5 \, V}{10 \, k\Omega} = 0.5 \, mA$.

The reading of the ammeter in the following circuit will be in $mA$.

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