The readings of the ammeter and voltmeter in | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) In the given $ LCR $ series circuit, the voltage across the inductor is $ V_L = 50 \, V $ and the voltage across the capacitor is $ V_C = 50 \, V

Vedclass · Accepted Answer

$ 2.2 \, A, 220 \, V $

Vedclass · Answer

(C) In the given $ LCR $ series circuit, the voltage across the inductor is $ V_L = 50 \, V $ and the voltage across the capacitor is $ V_C = 50 \, V $.Since $ V_L = V_C $, the circuit is in resonance.In a resonant $ LCR $ circuit, the net reactance is zero $( X_L - X_C = 0 )$, meaning the circuit behaves as a purely resistive circuit.Therefore, the entire source voltage drops across the resistor $ R $.Thus, the voltmeter reading is $ V_R = V_{source} = 220 \, V $.The current in the circuit is given by $ I = \frac{V_R}{R} = \frac{220 \, V}{100 \, \Omega} = 2.2 \, A $.Hence, the ammeter reading is $ 2.2 \, A $ and the voltmeter reading is $ 220 \, V $.

The readings of the ammeter and voltmeter in the following circuit are respectively:

Similar Questions

In a series $LCR$ circuit at resonance,the phase difference between voltage and current is

In a series $LCR$ circuit with $C = 2 \mu F$,$L = 1 \ mH$,and $R = 10 \ \Omega$,when the current in the circuit is maximum,what is the ratio of the energy stored in the capacitor to the energy stored in the inductor?

The current in resistance $R$ at resonance is

$A$ $L-C-R$ series $AC$ circuit is tuned to resonance. The impedance of the circuit is now . . . . . . .

With a gradual increase in the frequency of an $A.C.$ supply,the impedance of an $LCR$ series circuit

Vedclass Test Series

Exam Paper Generator

Online Exam Module