The readings of the voltmeter and ammeter in | vedclass

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(D) In the given circuit, there are two cells connected in series. The total electromotive force $(EMF)$ is $E_{eq} = 12 \, V - 6 \, V = 6 \, V$ (sinc

Vedclass · Accepted Answer

$7 \, V, 1 \, A$

Vedclass · Answer

(D) In the given circuit, there are two cells connected in series. The total electromotive force $(EMF)$ is $E_{eq} = 12 \, V - 6 \, V = 6 \, V$ (since they are connected in opposition).The total resistance of the circuit is $R_{total} = 4 \, \Omega + 1 \, \Omega + 0.6 \, \Omega + 0.4 \, \Omega = 6 \, \Omega$.The current in the circuit is $I = \frac{E_{eq}}{R_{total}} = \frac{6 \, V}{6 \, \Omega} = 1 \, A$.Thus, the ammeter reading is $1 \, A$.The voltmeter is connected across the $6 \, V$ cell. Since the current flows into the positive terminal of the $6 \, V$ cell, the cell is being charged.The terminal voltage of the $6 \, V$ cell is $V = E + Ir = 6 \, V + (1 \, A)(1 \, \Omega) = 7 \, V$.Therefore, the voltmeter reading is $7 \, V$ and the ammeter reading is $1 \, A$.

The readings of the voltmeter and ammeter in the circuit shown in the diagram are respectively

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