The reagent $X$ in the reaction sequence: $(CH_3)_3C-CH=CH_2$ $\xrightarrow[THF]{X} Y$ $\xrightarrow[NaOH]{NaBH_4} (CH_3)_3C-CH(OH)-CH_3$ is:

  • A
    $H_3O^{+}$
  • B
    $Hg(CH_3COO)_2$
  • C
    $OH^{-}$
  • D
    $HCOOH$

Explore More

Similar Questions

What are $X$ and $Y$ in the following reactions?
$CH_2O \xrightarrow[(ii) H_3O^+]{(i) X} CH_3(CH_2)_2CH_2OH$
$Y \xrightarrow[(ii) H_3O^+]{(i) C_2H_5MgBr} CH_3CH_2C(CH_3)_2OH$

Which one of the following will produce a primary alcohol by reacting with $CH_3MgI$?

Difficult
View Solution

The product in the following reaction is: $CH_3MgI + HCHO \to \text{Product}$

The product of the following reaction is ...............
$(CH_3)_3C-CH=CH_2 \xrightarrow[(ii) \, NaBH_4 + NaOH]{(i) \, Hg(CH_3COO)_2; \, THF} ?$

Difficult
View Solution

An alcohol,$X$ $(C_5H_{12}O)$ in the presence of $Cu / 573 \ K$ gives $Y$ $(C_5H_{10})$. The reactants required for the preparation of $X$ are

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo