The reagent used in the preparation of aspiri | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) Aspirin (acetylsalicylic acid) is prepared by the acetylation of the phenolic $-OH$ group of salicylic acid using acetic anhydride in the presence

Vedclass · Accepted Answer

$(CH_3CO)_2O / 	ext{Conc. } H_2SO_4$

Vedclass · Answer

(C) Aspirin (acetylsalicylic acid) is prepared by the acetylation of the phenolic $-OH$ group of salicylic acid using acetic anhydride in the presence of an acid catalyst like concentrated $H_2SO_4$. The reaction is: $	ext{Salicylic acid} + (CH_3CO)_2O \xrightarrow{	ext{Conc. } H_2SO_4} 	ext{Acetylsalicylic acid (Aspirin)} + CH_3COOH$ Therefore,the correct reagent is $(CH_3CO)_2O / 	ext{Conc. } H_2SO_4$.

The reagent used in the preparation of aspirin from salicylic acid is

Similar Questions

The points on the curve $9y^{2} = x^{3}$ where the normal to the curve makes equal intercepts with the axes are

$\int \frac{\cos ^3 x+\cos ^5 x}{\sin ^2 x+\sin ^4 x} d x=$

In the sequence of sets $(1,2,3), (4,5,6), (7,8,9,10), \ldots$,the sum of elements in the $50^{th}$ set is

When a positively charged particle enters a uniform magnetic field with uniform velocity,its trajectory can be :
$(1)$ a straight line
$(2)$ a circle
$(3)$ a helix

Which of the following is an oilseed crop?

Vedclass Test Series

Exam Paper Generator

Online Exam Module