The reciprocals of the square of the numbers | vedclass

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Question

(A) First,convert the mixed fractions into improper fractions:$1 \frac{1}{2} = \frac{3}{2}$$1 \frac{1}{3} = \frac{4}{3}$Next,find the square of these

Vedclass · Accepted Answer

$64: 81$

Vedclass · Answer

(A) First,convert the mixed fractions into improper fractions:$1 \frac{1}{2} = \frac{3}{2}$$1 \frac{1}{3} = \frac{4}{3}$Next,find the square of these numbers:$(\frac{3}{2})^2 = \frac{9}{4}$$(\frac{4}{3})^2 = \frac{16}{9}$Now,find the reciprocals of these squares:Reciprocal of $\frac{9}{4} = \frac{4}{9}$Reciprocal of $\frac{16}{9} = \frac{9}{16}$Finally,calculate the ratio of these reciprocals:Ratio $= \frac{4}{9} : \frac{9}{16} = \frac{4 	imes 16}{9 	imes 9} = \frac{64}{81}$Therefore,the ratio is $64: 81$.

The reciprocals of the square of the numbers $1 \frac{1}{2}$ and $1 \frac{1}{3}$ are in the ratio:

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