The refractive index of diamond is $2.42$. What is the meaning of this statement?

Vedclass pdf generator app on play store
Vedclass iOS app on app store
(N/A) The refractive index of a medium $n_m$ is related to the speed of light in that medium $v$ by the relation:
$n_m = \frac{\text{Speed of light in air}}{\text{Speed of light in the medium}} = \frac{c}{v}$
Where,$c$ is the speed of light in vacuum or air.
The refractive index of diamond is $2.42$. This suggests that the speed of light in diamond is reduced by a factor of $2.42$ compared to its speed in air.

Explore More

Similar Questions

Find out,from the table,the medium having the highest optical density. Also,find the medium with the lowest optical density.
Material mediumRefractive index
Air$1.0003$
Ice$1.31$
Water$1.33$
Alcohol$1.36$
Kerosene$1.44$
Fused quartz$1.46$
Turpentine oil$1.47$
Benzene$1.50$
Crown glass$1.52$
Canada Balsam$1.53$
Rock salt$1.54$
Carbon disulphide$1.63$
Dense flint glass$1.65$
Ruby$1.71$
Sapphire$1.77$
Diamond$2.42$

An object $5.0\, cm$ in length is placed at a distance of $20\, cm$ in front of a convex mirror of radius of curvature $30\, cm$. Find the position of the image,its nature and size.

Difficult
View Solution

Where should an object be placed in front of a convex lens to get a real image of the size of the object?

The radius of curvature of a spherical mirror is $20\, cm$. What is its focal length (in $cm$)?

Name the type of mirror used in the following situation.
Support your answer with a reason.
$(a)$ Headlights of a car

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo