The relation between the fraction of molecules $\left( \frac{N_E}{N_T} \right)$ and temperature is explained by the Boltzmann and Maxwell distribution graph.

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(N/A) When the temperature is raised,the maximum of the curve moves to a higher energy value and the curve broadens out,i.e.,it spreads to the right such that there is a greater proportion of molecules with much higher energies.
Mole fraction and Temperature:
The area under the curve must be constant since the total probability must be one at all times. According to the figure,increasing the temperature of the substance increases the fraction of molecules that collide with energies greater than $E_a$. It is clear from the diagram that in the curve at $(t+10)$,the area showing the fraction of molecules having energy equal to or greater than the activation energy increases significantly,leading to an increase in the rate of reaction.

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Similar Questions

An increase in temperature by $10\,^{\circ}C$,generally increases the rate of a reaction by .......... times.

The activation energy of a reaction is......

For an exothermic reaction $A \rightarrow B$,the activation energy is $15 \, K \, cal/mol$ and the heat of reaction is $5 \, K \, cal/mol$. The activation energy for the reverse reaction $B \rightarrow A$ will be ......... $K \, cal/mol$.

According to the Arrhenius equation,which of the following statements are correct?
$(A)$ $A$ high activation energy usually implies a fast reaction.
$(B)$ Rate constant increases with increase in temperature. This is due to a greater number of collisions whose energy exceeds the activation energy.
$(C)$ Higher the magnitude of activation energy,stronger is the temperature dependence of the rate constant.
$(D)$ The pre-exponential factor is a measure of the rate at which collisions occur,irrespective of their energy.

For a certain reaction,a large fraction of molecules has energy more than the threshold energy,yet the rate of reaction is very slow. Why?

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