The resistance in the following circuit is in | vedclass

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Question

(B) If the resistance were constant at $10 \, \Omega$,the steady current in the circuit would be $i = \frac{V}{R} = \frac{5 \, V}{10 \, \Omega} = 0.5

Vedclass · Accepted Answer

$i > 0.5 \, A$

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(B) If the resistance were constant at $10 \, \Omega$,the steady current in the circuit would be $i = \frac{V}{R} = \frac{5 \, V}{10 \, \Omega} = 0.5 \, A$.Since the resistance is increasing,the current through the circuit tends to decrease.According to Lenz's Law,the inductor opposes this change by inducing an electromotive force $(EMF)$ in the same direction as the main current to maintain the flow.Therefore,the induced current adds to the main current,resulting in a total current $i > 0.5 \, A$ at that instant.

The resistance in the following circuit is increased at a particular instant. At this instant,the value of resistance is $10 \, \Omega$. The current in the circuit will be now:

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