The resistance of a galvanometer is 25,Omega | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) Given:Galvanometer resistance,$G = 25\,\Omega$Full-scale deflection current,$i_g = 50\,\mu A = 50 	imes 10^{-6}\,A = 5 	imes 10^{-5}\,A$Required

Vedclass · Accepted Answer

$2.5 	imes 10^{-4}\,\Omega$

Vedclass · Answer

(A) Given:Galvanometer resistance,$G = 25\,\Omega$Full-scale deflection current,$i_g = 50\,\mu A = 50 	imes 10^{-6}\,A = 5 	imes 10^{-5}\,A$Required range of ammeter,$i = 5\,A$The formula for shunt resistance $S$ is given by:$S = \frac{G \cdot i_g}{i - i_g}$Since $i_g$ is very small compared to $i$,we can approximate $i - i_g \approx i$ or use the exact formula:$S = \frac{25 	imes 5 	imes 10^{-5}}{5 - 5 	imes 10^{-5}}$$S = \frac{125 	imes 10^{-5}}{4.99995} \approx \frac{125 	imes 10^{-5}}{5} = 25 	imes 10^{-5} = 2.5 	imes 10^{-4}\,\Omega$

The resistance of a galvanometer is $25\,\Omega$ and it requires $50\,\mu A$ for full-scale deflection. The value of the shunt resistance required to convert it into an ammeter of $5\,A$ range is:

Similar Questions

When a resistance of $100 \Omega$ is connected in series with a galvanometer of resistance $R$,its range is $V$. To double its range,a resistance of $1000 \Omega$ is connected in series. Find $R$. (in $\Omega$)

$A$ galvanometer acting as a voltmeter should have . . . . . . .

The current sensitivity of a moving coil galvanometer increases by $20 \%$ when its resistance is doubled. Calculate,by what factor does the voltage sensitivity change?

Assertion: To convert a galvanometer into an ammeter,a small resistance is connected in parallel with it.
Reason: The small resistance increases the combined resistance of the combination.

To convert a galvanometer into a voltmeter,one should connect a

Vedclass Test Series

Exam Paper Generator

Online Exam Module