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(C) The initial resistance of the wire is given by $R = \rho \frac{l}{A}$,where $l$ is the length and $A$ is the cross-sectional area.When the wire is

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$R/4$

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(C) The initial resistance of the wire is given by $R = \rho \frac{l}{A}$,where $l$ is the length and $A$ is the cross-sectional area.When the wire is bent at the middle by $180^o$ and the ends are twisted,the new length becomes $l' = \frac{l}{2}$ and the new cross-sectional area becomes $A' = 2A$.The new resistance $R'$ is given by $R' = \rho \frac{l'}{A'}$.Substituting the new values: $R' = \rho \frac{l/2}{2A} = \frac{1}{4} \left( \rho \frac{l}{A} \right) = \frac{R}{4}$.

The resistance of a wire is $R$. It is bent at the middle by $180^o$ and both the ends are twisted together to make a shorter wire. The resistance of the new wire is

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