The resistance of an ideal voltmeter is . . . . . . .

Given below are two statements:
Statement $I$: If the number of turns in the coil of a moving coil galvanometer is doubled,then the current sensitivity becomes double.
Statement $II$: Increasing the current sensitivity of a moving coil galvanometer by only increasing the number of turns in the coil will also increase its voltage sensitivity in the same ratio.
In the light of the above statements,choose the correct answer from the options given below:

How can we convert a galvanometer into an ammeter?

$A$ galvanometer of resistance $G$ is shunted by a resistance $S$. To keep the main current in the circuit unchanged,the resistance to be put in series with the galvanometer is

Give the difference between an Ammeter and a Voltmeter.

$A$ moving coil galvanometer, when shunted with a $2\text{ }\Omega$ resistance, gives a full-scale deflection for a current of $500\text{ mA}$. When a resistance of $470\text{ }\Omega$ is connected in series, it gives a full-scale deflection for a potential of $10\text{ V}$ applied across it. The value of the resistance of the galvanometer coil is . . . . . . $\Omega$.