The resonance energy of the following heteroc | vedclass

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(C) The resonance energy of heterocycles depends on the aromaticity and the electronegativity of the heteroatom. $1$. Pyridine is a six-membered aroma

Vedclass · Accepted Answer

pyridine $ > $ pyrrole $ > $ furan

Vedclass · Answer

(C) The resonance energy of heterocycles depends on the aromaticity and the electronegativity of the heteroatom. $1$. Pyridine is a six-membered aromatic ring similar to benzene,which possesses high resonance energy due to its stable aromatic sextet. $2$. Pyrrole and furan are five-membered aromatic rings. $3$. In pyrrole,the nitrogen atom donates its lone pair into the ring to complete the $6\pi$ electron system,making it more aromatic than furan. $4$. In furan,the oxygen atom is more electronegative than nitrogen,making it less effective at donating its lone pair into the ring,resulting in lower resonance energy compared to pyrrole. Therefore,the order of resonance energy is: $	ext{pyridine} > 	ext{pyrrole} > 	ext{furan}$.

The resonance energy of the following heterocycles is in the order:

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