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(A) To find the resultant capacitance between points $P$ and $Q$,we simplify the circuit step-by-step:$1$. The two capacitors of capacitance $C$ at th

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$3C$

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(A) To find the resultant capacitance between points $P$ and $Q$,we simplify the circuit step-by-step:$1$. The two capacitors of capacitance $C$ at the bottom are in parallel. Their equivalent capacitance is $C_{p1} = C + C = 2C$.$2$. This $2C$ is in series with the capacitor of $2C$ above it. Their equivalent capacitance is $C_{s1} = \frac{2C 	imes 2C}{2C + 2C} = \frac{4C^2}{4C} = C$.$3$. This $C$ is now in parallel with the other capacitor of capacitance $C$ in the middle. Their equivalent capacitance is $C_{p2} = C + C = 2C$.$4$. This $2C$ is in series with the top capacitor of $2C$. Their equivalent capacitance is $C_{s2} = \frac{2C 	imes 2C}{2C + 2C} = C$.$5$. Finally,this $C$ is in parallel with the rightmost capacitor of $2C$. The total equivalent capacitance is $C_{eq} = C + 2C = 3C$.

The resultant capacitance of the given circuit is

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