The root mean square velocity of one mole of | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The root mean square velocity of one mole of a monoatomic gas is given by $V_{rms} = \sqrt{\frac{3RT}{M}} \dots (1)$.The average kinetic energy $(

Vedclass · Accepted Answer

$V_{rms} = \sqrt{\frac{2E}{M}}$

Vedclass · Answer

(C) The root mean square velocity of one mole of a monoatomic gas is given by $V_{rms} = \sqrt{\frac{3RT}{M}} \dots (1)$.The average kinetic energy $(E)$ of one mole of a monoatomic gas is given by $E = \frac{3}{2}RT$.From this,we can express $RT$ as $RT = \frac{2E}{3} \dots (2)$.Substituting equation $(2)$ into equation $(1)$:$V_{rms} = \sqrt{\frac{3}{M} 	imes \frac{2E}{3}}$$V_{rms} = \sqrt{\frac{2E}{M}}$.

The root mean square velocity of one mole of a monoatomic gas having molar mass $M$ is $V_{rms}$. The relation between the average kinetic energy $(E)$ and the $V_{rms}$ is

Similar Questions

Which of the following gases will have the highest rate of diffusion?

Which of the following gases will have the lowest root mean square speed at $25\,^{\circ}C$?

Which of the following has maximum root mean square velocity at the same temperature?

The increasing order of the rate of diffusion for the gases $H_2$,$O_2$,$NH_3$,and $CO_2$ is:

The ratio of most probable velocity to that of average velocity is

Vedclass Test Series

Exam Paper Generator

Online Exam Module