The salt having the least solubility in water is

  • A
    $BaCl_2$
  • B
    $Ba(NO_3)_2$
  • C
    $MgSO_4$
  • D
    $BaSO_4$

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At $30\,^{\circ}C,$ the solubility of $Ag_2CO_3$ $(K_{sp} = 8 \times 10^{-12})$ would be greatest in one litre of

Calculate the solubility in $mol \ dm^{-3}$ of sparingly soluble salt $BA$ if its solubility product is $4.9 \times 10^{-13}$ at the same temperature.

Using the Gibbs energy change,$\Delta G^{o} = +63.3 \ kJ \ mol^{-1}$,for the following reaction in water at $25 \ ^{\circ}C$,calculate the solubility product constant $(K_{sp})$:
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$(R = 8.314 \ J \ K^{-1} \ mol^{-1})$

Find the solubility of $PbI_2$ if its solubility product is $7.0 \times 10^{-9}$.

The $K_{sp}$ for $BaSO_4$ at $25\ ^\circ C$ is $1.1 \times 10^{-10}$. To make the new solubility equal to $1.1 \times 10^{-8} \ M$,it is necessary to use a solution of $Na_2SO_4$ of the following concentration (in $M$):

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